下面哪一段代码会综合出latch（哪段儿代码更优雅，可读性更高，更Pythonic？）

哪段儿代码更优雅           ，可读性更高 
  
 
  
 
  
 
  
 
  
 
 ，更Pythonic？

题目要求

找出一个锯齿数组里长度大于5的子数组

在符合要求的子数组里的数据里找出所有偶数

如果数据小于10的话乘以2,大于10的除以2

最后统计符合要求的数据的和

测试数据

inputdata = [ [2,8,9,13,72,67,88,35,44], [33,28,47,2,10,45,66,92], [22,34,60,43,0,72,52], [10,11,53,58] ] print sum1(inputdata)

@蛙蛙王子 python

https://github.com/onlytiancai/codesnip/blob/master/python/goodorbad.py

def sum1(input): return sum((lambda x: x < 10 and x*2 or x/2)(num) for seq in inputdata if len(seq) >= 5 for num in seq if num % 2 == 0) def sum2(input): def getsublist(): for sublist in input: if len(sublist) >= 5: yield sublist def filterdata(sublist): for data in sublist: if data % 2 == 0: yield data def processdata(data): if data < 10: return data * 2 return data / 2 result = 0 for sublist in getsublist(): for data in filterdata(sublist): result += processdata(data) return result def sum3(input): return sum(num*2 if num < 10 else num/2 for seq in inputdata if len(seq) >= 5 for num in seq if num % 2 == 0)

@pw_网易有道 python

https://gist.github.com/1891339

def sum4(input): def filterList(matrix): return filter(lambda x: len(x) >= 5, matrix) def filterData(list): return filter(lambda x: x % 2 is 0, list) def processData(data): return data < 10 and data * 2 or data / 2 def reduceList(list): return reduce(lambda x, y: x + processData(y), filterData(list), 0) def reduceMatrix(matrix): return reduce(lambda result, list: result + reduceList(list), filterList(matrix), 0) return reduceMatrix(input)

@w1e3 python

sum(map(lambda x: x/((cmp(x, 10)+1) or 0.5), itertools.chain(*[filter(lambda x: not x%2, s) for s in inputdata if len(s) > 5])))

@Leksah Haskell

sum [ if y < 10 then y*y else y | x <-inputdata, length(x) > 5 , y <- x , y `mod` 2 ==0 ] i

@codeplayer Haskell

sum = sum . map (\x -> if x<10 then x*x else x) . filter ((==0) . (`mod` 2)) . concat . filter ((>5) . length)

@时蝇喜箭 Ruby

inputdata.select{|seq| seq.length > 5} .map{|seq| seq.select{|num| num % 2 == 0}.map{|num| num < 10? num*2 : num/2}} .flatten.inject(&:+)

@朴灵 Javascript&Underscore

_.chain(inputdata) .filter(function (arr) { return arr.length > 5; }) .map(function (arr) { return _.map(arr, function (num) { return num < 10 ? num * 2 : num; }); }) .flatten() .reduce(function (memo, num) { return memo + num; }, 0) .value();